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(B) The given reaction sequence is the Reimer-Tiemann reaction followed by oxidation:$1$. $Phenol$ reacts with $CHCl_3$ and $NaOH$ to form $o-hydroxyb

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(B) The given reaction sequence is the Reimer-Tiemann reaction followed by oxidation:$1$. $Phenol$ reacts with $CHCl_3$ and $NaOH$ to form $o-hydroxybenzaldehyde$ (Salicylaldehyde) as the major product $(A)$.$2$. The intermediate $A$ is already $Salicylaldehyde$. The step $\xrightarrow[H_3O^+]{} B$ typically refers to the acidification of the phenoxide intermediate to obtain the final aldehyde product $B$.$3$. Oxidation of $Salicylaldehyde$ $(B)$ using an oxidizing agent converts the $-CHO$ group into a $-COOH$ group, resulting in $Salicylic \ acid$ $(C)$.Therefore, the final product $C$ is $Salicylic \ acid$.

In the following sequence of the reaction, the final product "$C$" is:
$Phenol \xrightarrow[NaOH]{CHCl_3} A \xrightarrow[H_3O^+]{} B \xrightarrow[Oxidation]{} C$

Similar Questions

Identify the reaction shown below:
$C_6H_5OH + CH_2O \xrightarrow{\text{acid or base}} \text{o-hydroxybenzyl alcohol} + \text{p-hydroxybenzyl alcohol}$

Amongst the following,the total number of compounds soluble in aqueous $NaOH$ is:

Phenol on reaction with aqueous solution of bromine gives

Phenol $\xrightarrow{NaNO_2/H_2SO_4} B$ $\xrightarrow{H_2O} C$ $\xrightarrow{NaOH} D$. The name of the above reaction is:

$C_6H_5OH \xrightarrow{CH_3COCl / NaOH_{(aq)}} C_6H_5OCOCH_3$
The above reaction is an example of which of the following?

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In the following sequence of the reaction, the final product "$C$" is:$Phenol \xrightarrow[NaOH]{CHCl_3} A \xrightarrow[H_3O^+]{} B \xrightarrow[Oxidation]{} C$